An elevator descends into a mine shaft at the rate of 6m per minute. If the descent starts at 10 m
above the ground level, how long will it take to reach -350 m.
please answer it according to class 7
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Distance above ground level = 10m
Distance below ground level = 350m
Total distance = 350m + 10m
= 360m
Speed = 6m / min
Time = Distance / Speed
= 360 / 6
= 60 minutes
= 1 hour
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