Math, asked by BhaviniGupta, 2 months ago

An elevator descends into a mine shaft at the rate of 6m per minute. If the descent starts at 10 m

above the ground level, how long will it take to reach -350 m.
please answer it according to class 7​

Answers

Answered by mpsitearpit
2

Distance above ground level = 10m

Distance below ground level = 350m

Total distance = 350m + 10m

                        = 360m

Speed = 6m / min

Time = Distance / Speed

         = 360  / 6

         = 60 minutes

         = 1 hour

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Answered by gopalsinghbakal
1

Answer:

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