An elevator descends into a mine shaft at the rate of 6m per minute if the decent starts from 10 m above the ground level , how long will it take to reach 350 m
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Consider the elevator to be at constant speed and the destination to be 350m below ground level, the elevator has to travel 10m till the ground, then 350m more
So, total distance to travel is 360m
If the elevators speed is 6m/min,
Time=SpeedDistance
=6360
=60 minutes
=1 hour.
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