Math, asked by ahmedsaad200711, 6 months ago

An elevator descends into a mine shaft at the rate of 6metre per minute. What willbe its position after one hour? If it begins to descend from 20 m above the ground, what will be its position after 35minutes? i will mark u as brainliest

Answers

Answered by Kingsman252
2

Step-by-step explanation:

An elevator descends into mine shaft at the rate of 6 meter per minute. So, for 1 min elevator descends 6 meters. The position of the elevator after one hour =

We know,

1 hour =60 min 60 min x 6 meters=360 meters..

But the elevator began to descend from

20 meters above.

So,

360 - 20= " 340 meters." = It's position after 45 mins = 45 meters x 6 = mins

= 270 meters.

The elevator has descended from 15 meters above

So,

270 - 15 meters = 225 meters

MARK AS BRAINLIEST

Similar questions