Question

An elevator descends into a mine shaft at the rate of 7 m/min. If it starts

descending from 10 m above the ground level, how long will it take to reach

–410 m.​

Answer 1

Step-by-step explanation:

Total distance to be covered 420m

420m/7m per min

60 min or 1 hour

Answer 2

Answer:

1 hour

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be 410 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 420 m

If the elevator's speed is 7 metres/minute,

Then

Time= Distance/Speed

       = 420/7

       =60 minutes

       =1 hour

Thus the elevator would take 1 hour to reach its destination.