Math, asked by pratibhabhorkade, 23 days ago

An elevator descends into a mine shaft at the rate of 7 m/min. If the descend starts from 10 m above the ground level, how long will it take to reach the shaft 340 m below the ground level?

Answers

Answered by bookworm2008

15

Answer:

50 minutes

Step-by-step explanation:

Total distance = 340 + 10 = 350 meters

350 / 7 = 50 minutes to reach

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