An elevator descends into a mine shaft at the rate of 7m/min. If the descend starts from 20m above the ground, how long will it take to reach 400m deep from the ground?
Answers
Answered by
1
Answer:
dear student lakshana the answer is:-
The elevator starts from 20 m above the ground.
Therefore , total distance to be covered=(400+20)m=420 m.
Speed=7 m/min.
Therefore, time=D/S
=420/7 min
=60 min
=1 hr
Ans>The time taken is 1 hour.
if helpful mark as brainliest
Similar questions