An elevator descends into a mine shaft at the rate of 7m/min. If the descend start from 10 m above the ground level, how long will it take to reach the shaft 340 m below the ground level?
Answers
Answered by
8
Answer:
50 min
Step-by-step explanation:
total distance = 340m+10m=350m
speed. = 7m/min
time taken = 350/7 min
=50min
Answered by
6
Answer:
50 min.
I hope it is helpful for you
Similar questions