Math, asked by sharmaanushka2468, 6 months ago

An elevator descends into a mine shaft at the rate of 7m/min. If the descend start from 10 m above the ground level, how long will it take to reach the shaft 340 m below the ground level?

Answers

Answered by nitinguleria007

8

Answer:

50 min

Step-by-step explanation:

total distance = 340m+10m=350m

speed. = 7m/min

time taken = 350/7 min

=50min

Answered by anjaliagnihotri2007

6

Answer:

50 min.

I hope it is helpful for you

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