Question

An elevator descends into a mine shaft at the rate of 7m/min. If the descent starts from 20 m above the ground level, how long will it take to reach – 330 m

Answer 1

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$\huge\rm\underline\purple{Question :-}$

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.

$\huge\rm\underline\purple{Answer :-}$

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time= Distance/Speed

= 360/6

=60 minutes

=1 hour

Thus the elevator would take 1 hour to reach its destination.

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