An elevator descends into a mine shaft at the rate of 7m/min. If the descend starts from
5m above the ground level, how long will it take to reach -205m?
pls give explanation also behind how u got the ans and make the ans simply as possible bcuz i study in 7th
Answers
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Answer:
Given:-
Rate of movement = 7 m/min
Total distance = 210 m
To find:-
The time taken.
Solution:-
-205 m means 205 m below the ground level. Initially, the elevator is 5 m above the ground.
So, total distance travelled by the elevator = 205 + 5 = 210m
Time taken = distance/speed
t = 210 /7
t = 30 min
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