Math, asked by skzhyunnie807, 2 months ago

An elevator descends into a mine shaft at the rate of 7m/min. If the descend starts from
5m above the ground level, how long will it take to reach -205m?

pls give explanation also behind how u got the ans and make the ans simply as possible bcuz i study in 7th

Answers

Answered by tamanna1148
1

Answer:

Given:-

Rate of movement = 7 m/min

Total distance = 210 m

To find:-

The time taken.

Solution:-

-205 m means 205 m below the ground level. Initially, the elevator is 5 m above the ground.

So, total distance travelled by the elevator = 205 + 5 = 210m

Time taken = distance/speed

t = 210 /7

t = 30 min

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