An elevator descends into a mine shaft at the rate of 7m/min if he descent starts from 5m above the ground level,how long will it to reach -205m?
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Consider the elevator to be at constant speed and the destination to be 350m below ground level, the elevator has to travel 10m till the ground, then 350m more
So, total distance to travel is 360m
If the elevators speed is 6m/min,
Time=
Speed
Distance
=
6
360
=60 minutes
=1 hour.
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