Question

An elevator descends into a mine shaft at the rate of 7m per minute .what will be it's position after one hour

Answer 1

SOLUTION:
Distance the shaft goes down per min-7m
so, position of shaft after one hour-7 multiplied by 60
                                                       =420
    ans =420m

Answer 2

Time =60min
Speed =7m/min
Distance =s*t=420m
hope I helped you