An elevator descends into a mine shaft at the rate of 7metre per minute. If it begins to descend from 25 m above the ground, what will be its position after 45 minutes? Pls send explanation with working.
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Answer:
It will be 290 m below ground
Step-by-step explanation:
7 metres every minute fore 45 minutes would mean you multiply 7 by 45. Your answer would be 315. Since the elevator started 25 metres above the ground, you will subtract 25 from 315. this will get you 290. The elevator should be 290 metres below the ground after 45 minutes.
(If this is a multiple choice question, the answer maybe {-290 metres} instead of 290 metres)
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