an elevator descends into a mine shaft at the rate of 8 metre per minute. if the distant starts from 12 metre above the ground level, how long will it take to reach - 468 m
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Consider the elevator starts from 12 meter above.
The speed of elevator will be = 8m/min
Dis to cover = 468 and + 12m
= 490m
So time = dis/speed
= 490/8
= 61.1 mins
~ 1hour and 1 min
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