An elevator descends into a mine shaft at the rate of 8 m/min. If the descent starts from
35 m above the ground level, how long will it take to reach - 485 m?
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Answer:
65minutes
Step-by-step explanation:
total distance it has to cover is equal to 35+485 = 520
distance/speed = time
so 520/8 = 65 minutes
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