Math, asked by banerjeearpan347, 6 months ago

An elevator descends into a mine shaft at the rate of 8 m/min. If the descent starts from
35 m above the ground level, how long will it take to reach - 485 m?

Answers

Answered by manitgarg2004p3d57r
2

Answer:

65minutes

Step-by-step explanation:

total distance it has to cover is equal to 35+485 = 520

distance/speed = time

so 520/8 = 65 minutes

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