Math, asked by ychughbknr, 7 hours ago

An elevator descends into a mine shaft at the rate of 8 m/min.

If the descent starts from 120 m above ground level, how long

will it take to reach (-600 m)

Answers

Answered by ItzRonan

2

Answer:

total distance of descending = 120+600

= 720 m

distance = speed × time

time = 720/8

= 90 minutes

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