an elevator descends into a mine shaft at the rate of 8 m/min. If the descent starts from 10 m above the ground level.how long will it take to reach -350 m
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40 min approximately mark as brainliest
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Level above the ground=10 m
Level below the ground=-350 m
Therefore the total distance=(10-(-350) m=360 m
Speed = 8m/min
Time=Distance/Speed
=360/8
=45 minute
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