Question

An elevator descends into a mine shaft at the rate of 8m/min.If the descend starts from 12m above the ground level how long will it take to reach (-468m)

pls answer it is urgent​

Answer 1

Answer:

It will take 1 hour to reach -350 m.

Step-by-step explanation:

SOLUTION :  

Total distance covered by mine shaft = 10 - (- 350) = 10 + 350 = 360 m

Time taken to cover the distance 6 m = 1 min

Time taken to cover a distance of 1 m = 1/6 min

Time taken to cover a distance of 360 m = (1/6) × 360 = 60 min = 1 hour.

The elevator will reach - 350 m from 10 m in 1 hour.

Hence, it will take 1 hour to reach -350 m.

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Answer 2

+12meters

rate= 8m/min

8*X= -468

X=-468/8

X= -58 min