An elevator descends into a mine shaft at the rate of 8m/min. If the descent starts 20m above the ground level, find the time taken by the elevator to reach 460m below the ground level. plz answer it fast
Answers
Answered by
2
Step-by-step explanation:
total distance = 460+20 = 480 m
time = 480 / 8 = 60 min
Answered by
3
Answer:
60 min
Step-by-step explanation:
speed =distance
time
8= 460+20
t
t = 480÷ 8
t = 60
time = 60 minutes
Similar questions