Math, asked by dhairya335995, 7 months ago

An elevator descends into a mine shaft at the rate of 8m/min. If the descent start from 120?

above the ground level, how long will it take to reach 840? below the ground?​

Answers

Answered by lancedavebadillo
0

Answer:

12455321566788888888

Answered by Anonymous
0

Answer:

60 minutes

Step-by-step explanation:

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360 m=  

(−6)

(−360)

​  

 ------- [from the formula : speed=  

time

distance

​  

]

=60 minutes

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