Question

An elevator descends into a mine shaft at the rate of 8m/min .If the descend starts from 12 m above the ground level, How long will it take to reach -468 m ​

Answer 1

Answer:

Consider the elevator to be at constant speed and the destination to be 350m below ground level, the elevator has to travel 10m till the ground, then 350m more

So, total distance to travel is 360m

If the elevators speed is 6m/min,

Time=

Speed

Distance

=

6

360

=60 minutes

=1 hour.