Math, asked by yadavprince8800, 16 days ago

An elevator descends into a mine shaft at the rate of 8m/min. if the descent starts from 12m above the ground level, how long it will take to reach -380m.​

Answers

Answered by saionrajrahaman98
2

Step-by-step explanation:

total distance cover by elevator=380+12= 392 m

now ,,time taken by elevator to cover that distance with speed of 8m/min is

=392/8 min= 49 min

Answered by aryansingh13620
0

Answer:

49 MIN heheheheheheheheheheh

Answered by aryansingh13620
0

Answer:

49 MIN heheheheheheheheheheh

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