An elevator descends into a mine shaft at the rate of 8m/min. if the descent starts from 12m above the ground level, how long it will take to reach -380m.
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Step-by-step explanation:
total distance cover by elevator=380+12= 392 m
now ,,time taken by elevator to cover that distance with speed of 8m/min is
=392/8 min= 49 min
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0
Answer:
49 MIN heheheheheheheheheheh
Answered by
0
Answer:
49 MIN heheheheheheheheheheh
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