Question

An elevator descends into a mine shaft at the rate of6 m\ min. If it begins to descends from 20 m above the ground, what will be its position after45 minutes?

Answer 1

Answer:

After 45 minutes it will be 250m below ground.

Step-by-step explanation:

Speed= 6m/min

Time = 45 minutes

and the elevator starts 20m above ground

first multiply 45 with 6

45 x 6 = 270m

then subtract the distance above the ground from which the elevator starts to descend from.

270m - 20m = 250m.

∴ Hence the elevator is 250m below ground or -250m form ground level.

Answer 2

Answer:

Answer:

The answer is 250m

Because if we will multiply 6 to 20 ans is 270 .

After that we will subtract 270 from 20 we will get the answer - 250m .

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Step-by-step explanation: