Question

an elevator descends into a mine shaft at the rateof 6m/min if the descent starts from 10m above the ground level how long will it take to reach _350m

Answer 1

Answer:

6 minutes

Step-by-step explanation:

Starting of the descend : 10 meters above ground level

Meters at the end of descend : 350 meters

Rate of descending : 6  meters per minute

60 x 6 minutes = 360 minutes ( 350 + 10 )

= 10 meter above the ground + 350 meters = 360...

Answer 2

Answer:

Distance descended is denoted by a negative integer.

Distance descended is denoted by a negative integer.Initial height = + 10 m

Distance descended is denoted by a negative integer.Initial height = + 10 mFinal depth = -350 m

Distance descended is denoted by a negative integer.Initial height = + 10 mFinal depth = -350 mTotal distance to be descended by the elevator = (-350) - (+ 10) = -360 m

Distance descended is denoted by a negative integer.Initial height = + 10 mFinal depth = -350 mTotal distance to be descended by the elevator = (-350) - (+ 10) = -360 mTime taken by the elevator to descended - 6 m = 1 min

Distance descended is denoted by a negative integer.Initial height = + 10 mFinal depth = -350 mTotal distance to be descended by the elevator = (-350) - (+ 10) = -360 mTime taken by the elevator to descended - 6 m = 1 minThus, time taken by the elevator to descend - 360 m = (-360) ÷ (- 6)

Distance descended is denoted by a negative integer.Initial height = + 10 mFinal depth = -350 mTotal distance to be descended by the elevator = (-350) - (+ 10) = -360 mTime taken by the elevator to descended - 6 m = 1 minThus, time taken by the elevator to descend - 360 m = (-360) ÷ (- 6)= 60 minutes