Math, asked by neharaniparmar, 7 hours ago

An elevator descends into a mine
shaft of the rate 5m/min it
the descent starts from 8 m above the ground level how long will
it takon to reach 42m (means-42)
below the ground level)
full explain plz

Answers

Answered by chandajha2280

0

Answer:

Answer = 10m/min

Step-by-step explanation:

sum of distance = 50m

speed = 5 m/min

time = distance/speed

50/5=10m/sec

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