Math, asked by gbramsinghpur, 8 months ago

An elevator descends into a mine shaft of the rate 6 meter per minute. how long will it take to reach (-370)my. if the descent start from 50 above the ground level.
explain In detail nd -370 how can change into positive in this question ​

Answers

Answered by diyababu29
1

Answer:

300 m below ground level.

Step-by-step explanation:

Sol: Since the elevator is going down, the distance covered by it will be

represented by a negative integer.

Change in position of the elevator in one minute = – 5 m

Position of the elevator after 60 minutes = (–5) × 60 = – 300 m

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