Question

an elevator descends into a mine shift at rate of 6 m/min.if the descent starts from 10 m above the ground level,how long will it take to reach -350 m.

Answer 1

360/6 = 60 min......

Answer 2

$\bigstar$Question :

An elevator descends into a mine shift at rate of 6 m/min.if the descent starts from 10 m above the ground level,how long will it take to reach -350 m.

$\bigstar$Solution :

$\: ⇢$Starting position of mine shaft is 10 m above the ground but it moves in opposite direction so it travels the distance (-350)m below the ground.

$\: ⇢$So total distance covered by mine shaft = 10 m - (-350) m = 10 + 350 = 360 m.

$\: ⇢$Now time taken to cover a distance of 6 m by it = 1 minute

$\: ⇢$So time taken to cover a distance of 1 mby it = $\sf{ \dfrac{1}{6}}minute$

$\: ⇢$Therefire,time taken to cover a distance of 360 m = $\sf{ \dfrac{1}{6}}×360$

We know that,

= 60 minutes = 1 hour

(Since 60 minutes = 1 hour)

$\: ⇢$Thus,In one hour the mine shaft reaches -350 below the ground.