Question

an elevator descends into a mineshaft at the rate of 10m/min. if the decent starts from 250m above the ground level ,how long will it take to reach (-450m)​

Answer 1

Answer:

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be -450 m below ground level,

The elevator has to travel 250m till the ground, then -450 m more.

So, the total distance to travel is 200 m

If the elevator's speed is 10 metres/minute,

Then

Time= Distance/Speed

       = 200/10

       =20 minutes

Thus the elevator would take 20 minutes  to reach its destination.