. An elevator descends into a mineshaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -650 m?
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Answer:
Distance descended is denoted by a negative integer,
Initial height =+10 m
Final Depth =−350 m
Total distance to be descended by the elevator =(−350)−(+10)=−360 m
Given, the time is taken by the elevator to descend −6 m=1 minute
Thus, time taken by the elevator to descend −360 m=
(−6)
(−360)
------- [from the formula : speed=
time
distance
]
=60 minutes
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