Question

An elevator descends into a mineshaft at the rate of 6 meter per minute.
i) What will be its position after one hour?
ii) If it begins to descend from 15 meter above the ground, what will be its position after 40 minutes? with step by step explation.

Answer 1

i) Position=-6x60(min)
=-360m
ii)Position=(-6x40(min))+15
=-240+15
=-225m

Hope it is helpful
Please mark me the brainliest
Thank you

Answer 2

Answer:

(i)The position the elevator descends in one minute=6 minutes

Position the elevator will be after 1hr/60 minute=(60×6)m=360m

(ii)Position the elevator is=15m

Position in which the elevator will be after 40mins of descending=(15-(40×6))m= (15-240)m= -225m below the ground.