an elevator descends into a mineshaft at the rate of 6m/min.if descent starts from 10m above the ground level how long will it take to reach -350m
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Total distance covered by mine shaft= 10-(-350) = 10+350=360 m
Time taken to cover the distance 6 m =1 min
Time taken to cover a distance of 1 m = 1/6 min
Time taken to cover a distance of 360m = (1/6)×360 = 60 min = 1 hour.
The elevator will reach -350 m from 10 m in 1
hour.
Time taken to cover the distance 6 m =1 min
Time taken to cover a distance of 1 m = 1/6 min
Time taken to cover a distance of 360m = (1/6)×360 = 60 min = 1 hour.
The elevator will reach -350 m from 10 m in 1
hour.
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