An elevator descends into a mineshaft at the rate of 6m/min. If the descent starts from 10m above the ground level, how long will take to reach -350m.
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Given:
An elevator descends into a mineshaft at the rate of 6m/min. If the descent starts from 10m above the ground level
To find:
How long will take to reach -350m.
Solution:
From given, we have,
An elevator descends into a mine shaft at the rate of 6m/min. The descent starts from 10m above the ground level.
The total distance covered by an elevator is given by,
Total distance = 10 m + 350 m
The speed of elevator = 6 m/min
we use the formula,
Speed = Distance / Time
Time = total distance / speed
Time = (350 + 10) / 6
Time = 360/6
Time = 60 minutes
Therefore, the time taken by an elevator to reach -350m is 60 min.
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