Question

An elevator descends into a mineshaft at the rate of 6m/min. If the decent starts from 10m above the ground how long it will take to -350m​

Answer 1

Answer:

1 hour

Step-by-step explanation:

Total distance elevator has to travel = Initial position - Final position

                                                            = 10 - (-350)

                                                            = 10 + 350

                                                            = 360 m

Now ,

Elevator descends at rate 6 m / min

∴ Elevator travels 6 m in =  1 min

Elevator travels 1 m in = 1/6 min

Elevator travels 360 m in = 1/6 × 360 minutes

                                          = 60 minutes

                                           = 1 hour

Hence , it will take the elevator 1 hour.

Answer 2

Answer:

1 hour

Step-by-step explanation:

total distance = 350 m + 10 m

= 360m

time taken = total distance / rate of travel = 360/6 =  60 min. = 1 hour