Question

An elevator descends into a mineshaft at the rate of 6m/min. If the descent starts from 10 m above the
ground level, how long will it take to reach (350) m.​

Answer 1

Answer:

MATHS

ANSWER

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360 m=

(−6)

(−360)

------- [from the formula : speed= time/distance

=60 minutes