an elevator descends into a mineshaft at the rates of 6meters per minute if the descends stands from 10m above the ground level how long will it take to reach
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Answer:
Total distance covered by an elevator = 10 - (-350) m
= 10 + 350
= 360 m
Time taken to cover a distance of 6 m = 1 min
Therefore, time taken to cover 360 m = 360 ÷ 6
= 60 minutes
= 1 hour (1 hour = 60 minutes)
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