An elevator descends into a shaft at the rate of 7m/min. If the descent starts from 15m above the ground level, how long will take to reach 475m?
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Answer:
the total height for the mineshaft to cover is 475+15= 490 m
for covering the distance the mineshaft requires=(490/7 )min
=70 min
= 1hr 10 min
Step-by-step explanation:
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