Question

An Elevator descends into mine shaft at the rate of 5 m/min is the descent starts from 10m above
ground level how long will take to reach - 400m?​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Time=82\:min}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Initial \: speed = 5 \: min/m \\ \\ \tt: \implies Total\:Distance(s) = 410 \: m \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Time \: of \: desecent = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt:\implies Time = \frac{Distance}{Speed} \\ \\ \tt:\implies Time = \frac{410}{5} \\ \\ \green{\tt:\implies Time = 82 \: min} \\ \\ \bold{Alternate \: method} \\ \tt:\implies s = ut + \frac{1}{2} a {t}^{2} \\ \\ \tt:\implies 410= 5 \times t + \frac{1}{2} \times 0 \times {t}^{2} \\ \\ \tt:\implies 410 = 5 \times t \\ \\ \tt:\implies t = \frac{410}{5} \\ \\ \green{\tt:\implies t = 82 \: min}$

Answer 2

$\tt{\orange {\huge{--------}}} B.Q$

QUESTION :

An Elevator descends into mine shaft at the rate of 5 m/min is the descent starts from 10m above ground level how long will take to reach - 400m?

SOLUTION :

This is an extremely easy and simple question...

Total Distance = 10 m.- ( - 400 m ) = 410 m.

Rate = 5 m / min.

Now,

Time = Displacement / Speed = 410 / 5 min

=> 82 mins.

=> 1 hour 22 mins...........[ A ]