An elevator descends into mine shaft at the rate of 5 m per minute . If the descent starts from 30m above the ground level , find the time taken by the elevator to reach 300m
Answers
Step-by-step explanation:
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Mathematics
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Chapters in NCERT Solutions - Mathematics, Class 7
Exercises in Integers
Question 53
Q7) An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.
Solution
Transcript
Solution 7:
Starting position of mine shaft is = 10m above ground
but,
it moves in opposite direction so it travels the distance (-350 m ) below the ground.
Total distance covered by mine shaft = 10m - (-350m)
= 10 + 350
= 360m
Now, taken to cover a distance of 6m by it = 1 minute
Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min
Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \
60 minutes = 1 hour
thus, in one hour the mine shraft reaches = 350 below the ground.