an elevator descends into mine shaft at the rate of 5m/min . if it decents from 20 metre above the ground level how long it will take to reach - 330 m. With full solutions
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Answer:
the answer is 1 hr 10 mins
Step-by-step explanation:
-330 m means 330 m below the ground level.
Presently, the elevator is at 20 m above ground level.
Therefore, total distance travelled = 330+20= 350.
The rate = 5m/min
hence, time taken= total distance/ rate of travel
= 350/5 = 70 mins
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