Question

An elevator descends into mine
shaft at the rate of 6m /min. If
the descent starts from 10m above the ground level, how long will it take to reach - 350m.
explanation please​

Answer 1

Answer:

1 HOUR

Step-by-step explanation:

initial position of the elevator = +10

final position of the elevator = -350

total didtance moved = -350 - 10 m

                                    =-360 m

rate of decent = -6 m per minute

total time = distance /speed

                = -360/ -6 m

                =1 hour