Question

An elevator descends into mine shaft at the rate of 6m /min. If the descent starts from 10m above the ground level, how long will it take to reach - 350m. explanation please ......FOLLOW ME =FOLLOW U BACK...

Answer 1

initially elevator is at 10 metre above the ground.

it also go more above about 350 metre.

so. total distance=350+10

= 360

now, total distance/rate of travel

$\: \: \: \: \: \: \: \: \: = \frac{360}{6}$

$= 60minute$

means= 1hour

Answer 2

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