An elevator descends into mine shaft at the rate of 7m per minute. If it descent starts from 20m above the ground level, find the time taken by the elevator to reach 400m .
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The Brainliest Answer! The elevator starts from 20 m above the ground. Therefore , total distance to be covered=(400+20)m=420 m. Speed=The elevator starts from 20 m above the ground.
Therefore , total distance to be covered=(400+20)m=420 m.
Speed=7 m/min.
Therefore, time=D/S
=420/7 min
=60 min
=1 hr
Ans>The time taken is 1 hour.
Therefore , total distance to be covered=(400+20)m=420 m.
Speed=7 m/min.
Therefore, time=D/S
=420/7 min
=60 min
=1 hr
Ans>The time taken is 1 hour.
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