Math, asked by prakashu5020, 18 days ago

An elevator descent in to a mine shaft at the rate of 8m/min. if the descents starts from 18 m above the ground level ,how long will it take to reach -225 m.

Answers

Answered by arunprasad1981
1

Answer:

Mark as Brainliest

Step-by-step explanation:

Total distance covered from A to C =12+468=480 m

Speed =8 m/min

Therefore, time =

Speed

Total distance covered

time=

8/480

=60 minutes.

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