An elevator descent into a mine shaft at the rate 6m/min.if the descent start from 10m.above the groud level how long will it take to reach -350m.
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The elevator have to travel a total distance of 350+10=360m
so time taken to reach -350 is=distance÷speed
= 360÷6
= 60 min
so time taken to reach -350 is=distance÷speed
= 360÷6
= 60 min
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