Question

an elevator descent into a mine shaft at the rate of 6 m/min if the descent start from 10m above the ground level how much will it take to reach_ 350​

Answer 1

Answer:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level, The elevator has to travel 10m till the ground, then 350 m more. Thus the elevator would take 1 hour to reach its destination.

mark brainlist ans

Answer 2

Answer:

60min

Explanation:

it descent 5m/min

so time taken to descent=(350+10)/6=60

hence ans = min

if you like it pls mark as brainliest.

and follow me