Question

An elevator descents into a mine shaft at the rate of 6m/minute. If the descent starts from 20m above the ground level, how long it will take to reach -370m?

Answer 1

see the attachment

Total descent= 370+20= 390
or -370-30= -390
distance should be positive so it is 390
Time =
$\frac{distance}{speed} \\ = > \frac{390}{6} = 65minutes$
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