Question

an elevator desends into a mine shaft at rate of 5m/min . if descent starts from 10m , how long will it take to reach -360m?​

Answer 1

Answer:

Rate it descends = 5m/min

Starting point =+10m

Has to reach = - 360m

therefore distance = 360+10

=370 m

time = speed/distance

= 370/5

Ans. 74 mins or 1 hour 14 minutes

Answer 2

Step-by-step explanation:

› Given :-

• 5 m/min
• Descent starts from 10m

› Solution :-

$Rate :- 5 m/min \:$

$→ starting, point$ :- 10m

Has to reach : - 360 m

Then , total distance = 360 + 10

=> 370 m

$Formula :- Time = Distance/Speed$

=> 370 ÷ 5

=> 1 hours 14 minutes

≈> Answer :- 1 hour 14 minutes