Math, asked by Koppunurivaruntej, 4 months ago

An elevator desends into a mine shaft at the rate of 6 meters per min​

Answers

Answered by scientist331
3

Answer:

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360 m=

(−6)

(−360)

------- [from the formula : speed=

time

distance

]

=60 minutes

Answered by kaviramesh203
0

Step-by-step explanation:

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.

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