An elevator discends into a mine shaft at the rate of 6m/min. If the descent starts from 10m abave the ground level,how long well it take to reach -350
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Hi friend!
It will take 1 hour, that is 60 mins.
Total distance to cover = 350 + 10m
=360m
speed = 6mpm
Time = Distance/Speed
= 360/6 mins
= 60 mins.
Hope you found my answer useful .
It will take 1 hour, that is 60 mins.
Total distance to cover = 350 + 10m
=360m
speed = 6mpm
Time = Distance/Speed
= 360/6 mins
= 60 mins.
Hope you found my answer useful .
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