an elevator dscends into mineshaft at the rate of 5 m per min if descend from 20 m above the ground level how long it will take to reach -330m
Answers
Answer:
Considering the elevator to be at constant speed and the destination to be 350 m below ground level,
The elevator has to travel 10m till the ground, then 350 m more.
So, the total distance to travel is 360 m
If the elevator's speed is 6 metres/minute,
Then
Time= Distance/Speed
= 360/6
=60 minutes
=1 hour
Thus the elevator would take 1 hour to reach its destination.
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Answer:
Considering the elevator to be at constant speed and the destination to be 350 m below ground level,
The elevator has to travel 10m till the ground, then 350 m more.
So, the total distance to travel is 360 m
If the elevator's speed is 6 metres/minute,
Then
Time= Distance/Speed
= 360/6
=60 minutes
=1 hour
Thus the elevator would take 1 hour to reach its destination.
Step-by-step explanation: