Question

an elevator dscends into mineshaft at the rate of 5 m per min if descend from 20 m above the ground level how long it will take to reach -330m​

Answer 1

Answer:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time= Distance/Speed

       = 360/6

       =60 minutes

       =1 hour

Thus the elevator would take 1 hour to reach its destination.

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Answer 2

Answer:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time= Distance/Speed

      = 360/6

      =60 minutes

      =1 hour

Thus the elevator would take 1 hour to reach its destination.

Step-by-step explanation: