Math, asked by Anum246, 9 months ago

An elevator goes down at the rate of 3 m per minute. If it starts going down from a height of 20 m above the ground level, find the time taken by the elevator to reach 100 m below the ground level. (Consider the distance above the ground level to be a positive integer and that below the ground level by a negative integer.)

Answers

Answered by devsinghal164
2

Answer:

PLZ FOLLOW ME AND MARK THIS ANS AS BRAINLIEST

Step-by-step explanation:

Total distance covered from A to C =12+468=480 m

Speed =8 m/min

Therefore, time =

Speed

Total distance covered

time=

8

480

=60 minutes.

Answered by Anonymous
9

Question:

An elevator goes down at the rate of 3 m per minute. If it starts going down from a height of 20 m above the ground level, find the time taken by the elevator to reach 100 m below the ground level.

(Consider the distance above the ground level to be a positive integer and that below the ground level by a negative integer.)

Answer:

40 minutes.

Step-by-step explanation:

Initial position of the elevator will be represented by 20. (Since it is 20 m above the ground level)

Final position of the elevator will be represented by  −100. (Since it is 100 m below the ground level)

The distance elevator goes down in one minute is 3 m which will be represented by −3.

Time taken by the elevator = ( Final position  − Initial position) ÷ Rate at which it goes down.

[−100−20]÷(−3)

= (−120)÷(−3)

= 40

Hence, the elevator will reach 100 m below the ground level after 40 minutes.

( Answered By Manan Khurma - Teacher ) , ( Answer Written By Kiran )

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